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2x^2+x+10=5
We move all terms to the left:
2x^2+x+10-(5)=0
We add all the numbers together, and all the variables
2x^2+x+5=0
a = 2; b = 1; c = +5;
Δ = b2-4ac
Δ = 12-4·2·5
Δ = -39
Delta is less than zero, so there is no solution for the equation
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